(-2x^-3y/5x^2y^-5)^-2

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Solution for (-2x^-3y/5x^2y^-5)^-2 equation: 


D( x )

x^2*((-2*x^-3*y)/5)*y^-5 = 0

x = 0

x^2*((-2*x^-3*y)/5)*y^-5 = 0

x^2*((-2*x^-3*y)/5)*y^-5 = 0

-2/5*x^-1*y^-4 = 0 // : -2/5*y^-4

x^-1 = 0

x należy do O

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(x^2*((-2*x^-3*y)/5)*y^-5)^-2 = 0

25/4*x^2*y^8 = 0 // : 25/4*y^8

x^2 = 0

x = 0

x in { 0} 

x belongs to the empty set

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